how to solve subnetting Question ? for C class ip address
Hii guys today we will learn how to solve subnetting question before .if you want to know more information about ip address an subnet mask so click on my link and visit about IP address, subnet mask and its binary conversion
so let we start we will solve C CLASS IP ADDRESS SUBMIT MASK
| 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1 | ip address |
| 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 192 |
| 1 | 0 | 1 | 0 | 1 | 0 | 0 | 0 | 168 |
| 0 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 5 |
| 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 |
192.168.5.1
| IP ADDRESS | 192 | 168 | 5 | 1 |
| SUBMIT MASK | 255 | 255 | 255 | 0 |
| BINARY CONVERTION | 110000 | 10101000 | 00000101 | 0000001 |
192.168.5.1/28
11111111.1111111.11111111.11110000
X =is number of off bit in octate Y= is all on bit Z=Which octate in change his off bit
X=4 Y=6 Z=6
Number of subNetwork 2^x 2^4 =16
Numbwr od HostNetwork 2^y-2 =16-2 14
Block Size 2^z 2*4 = 16
| NETWORK ADDRESS | 1ST HOST ASSRESS | LAST HOST ADDRESS | BRODCAST ADDRESS |
| 192.168.5.0 | 192.168.5.1 | 192.168.5.14 | 192.168.5.15 |
| 192.168.5.16 | 192.168.5.17 | 192.168.5.30 | 192.168.5.31 |
| 192.168.5.32 | 192.168.5.31 | 192.168.5.46 | 192.168.5.47 |
| 192.168.5.48 | 192.168.5.47 | 192.168.5.62 | 192.168.5.63 |
| 192.168.5.64 | 192.168.5.65 | 192.168.5.78 | 192.168.5.79 |
| 192.168.5.80 | 192.168.5.81 | 192.168.5.94 | 192.168.5.95 |
| 192.168.5.96 | 192.168.5.97 | 192.168.5.110 | 192.168.5.111 |
| 192.168.5.128 | 192.168.5.129 | 192.168.5.142 | 192.168.5.143 |
| 192.168.5.144 | 192.168.5.145 | 192.168.5.158 | 192.168.5.159 |
| 192.168.5.160 | 192.168.5.161 | 192.168.5.174 | 192.168.5.175 |
| 192.168.5.176 | 192.168.5.177 | 192.168.5.190 | 192.168.5.191 |
| 192.168.5.192 | 192.168.5.193 | 192.168.5.207 | 192.168.5.207 |
| 192.168.5.208 | 192.168.5.209 | 192.168.5.222 | 192.168.5.223 |
| 192.168.5.224 | 192.168.5.225 | 192.168.5.238 | 192.168.5.239 |
| 192.168.5.240 | 192.168.5.241 | 192.168.5.22 | 192.168.5.255 |
(note- how to configure in system you will look my next artical in this )
Thank you
by vishnu sharma
